Hydrogen Gas

Purpose: To determine the percent yield of hydrogen hazardous produced in the reaction of magnesium with hydrochloride hot Materials: Electronic equipoise scale splatter measuring tube 10mL or 25mL alumnus cylinder Retort stand and clamp chiliad mL graduated cylinder containing about 800mL of water supply which has been brought to mode temperature horseshit wire 1 hole 00 rubber stopper 2.5 cm gaffe of Mg ribbon steel wool 6 seawall of dm3 HCL(aq) information Table1: Quantitative observations of magnesium reacting with hydrochloride acid Substances cadence including uncertainty Mass of 2.5cm magnesium 0.037g±0.0005 mode temperature19°C±0.5 mass of 6.00 dm3 HCL(aq) used15.1cm3 ±0.5 Volume of bollixoline collected (water levels are equal to room pressure)36.5cm3 ±0.1 duration of magnesium2.6cm±0.05 Table2: Qualitative observations of the magnesium, reacting in the hydrochloride acid SubstancesQualitative Observations 2.

5cm Magnesium (Mg) ribbon dissect away thin strip hard Shiny bendable Hydrochloride acid (HCL)Transparent bonny like water The reaction occurred when the hydrochloride acid reaches the magnesium (Mg) ribbon startle to dissolve Separating the H2 bobble from the water gas bubbles attached to copper wire by and by the reaction occurred (the period of 5 minutes waiting for the gas in the test tube to come to room temperature)No to a greater extent air bubbles No change of colour Transparent water Gas bubbles attached to copper coil Temperature of the water by and by the reaction19.5 °C ±0.5 Pressure101.38kPa Calculations:! Step 1: Equation Mg(s) + 2HCL (aq) MgCl2 (aq) + H2 (g) Step 2: pose the number of moles of Mg n = m/M Molar mass of Mg = 24.31g/mol m = 0.037±0.0005g n = 0.037±0.0005g ÷ 24.31g/mol n = 1.52x10-3 ±0.0005mol Uncertainty Calculations: 0.0005 ÷ 0.037g x coke = 1.4% 0.0005 ÷24.31g/mol x 100 = 0.002% 1.4% + 0.002% = 1.402% 1.402% of 0.037 = 0.0005 Therefore the uncertainty is ±0.0005 Since the...If you fate to keep a full essay, order it on our website: BestEssayCheap.com

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